((3x^2+7x-20)(x-1)^3(x+3))/(x+4)

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Solution for ((3x^2+7x-20)(x-1)^3(x+3))/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

((3*x^2+7*x-20)*(x-1)^3*(x+3))/(x+4) = 0

3*x^2+7*x-20 = 0

3*x^2+7*x-20 = 0

DELTA = 7^2-(-20*3*4)

DELTA = 289

DELTA > 0

x = (289^(1/2)-7)/(2*3) or x = (-289^(1/2)-7)/(2*3)

x = 5/3 or x = -4

(x+4)*(x-5/3) = 0

(x-5/3)*(x-1)^3*(x+3) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-1 )

x-1 = 0 // + 1

x = 1

( x-5/3 )

x-5/3 = 0 // + 5/3

x = 5/3

x in { -3, 1, 1, 1, 5/3 }

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